If we know the molar mass of a certain aspect and also Avogadro"s consistent, just how have the right to we calculate the mass of a solitary atom? Do we have to multiply the molar mass via Avogadro"s constant?


*

*

For many atoms it"s around Ryan"s answer.

You are watching: How to find the mass of a single atom

E.g. Carbon-12:

$$fracce12 g~ceCpu1 mol~ceC imes fracpu1 mol~ceCpu6.022E23 atoms =pu1.993E-23 g//atom = pu1.993E-27 kg//atom.$$

That was the molar mass $M$ multiplied by $1/N_mathrmA$, wbelow $N_mathrmA$ is Avagadro"s consistent.

Therefore $M/N_mathrmA$ offers you a calculation for mass of an atom for the certain element.


*

*

The average mass of a single aspect is its atomic mass on the periodic table (measured in $puu$, the combined atomic mass unit). One $puu$ equates to about $pu1.661E-27 kg$.


*

Thanks for contributing a response to slrfc.org Stack Exchange!

Please be certain to answer the question. Provide details and share your research!

But avoid

Asking for assist, clarification, or responding to various other answers.Making statements based upon opinion; ago them up through recommendations or personal suffer.

Use MathJax to format equations. MathJax referral.

See more: Brit Is The Wife Of Bath A Feminist ? Canterbury Tales 3

To learn more, check out our tips on writing good answers.


Post Your Answer Discard

By clicking “Article Your Answer”, you agree to our regards to company, privacy policy and cookie policy


Not the answer you're looking for? Browse various other inquiries tagged mole or ask your own question.


Do I need to think about the molecular mass of the oxygen atom or the diatomic oxygen molecule as soon as determining the empirical formula of an iron oxide?
site design / logo © 2021 Stack Exchange Inc; user contributions licensed under cc by-sa. rev2021.9.2.40142


Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange deserve to keep cookies on your tool and disclose indevelopment in accordance through our Cookie Policy.