For many atoms it"s around Ryan"s answer.
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$$fracce12 g~ceCpu1 mol~ceC imes fracpu1 mol~ceCpu6.022E23 atoms =pu1.993E-23 g//atom = pu1.993E-27 kg//atom.$$
That was the molar mass $M$ multiplied by $1/N_mathrmA$, wbelow $N_mathrmA$ is Avagadro"s consistent.
Therefore $M/N_mathrmA$ offers you a calculation for mass of an atom for the certain element.
The average mass of a single aspect is its atomic mass on the periodic table (measured in $puu$, the combined atomic mass unit). One $puu$ equates to about $pu1.661E-27 kg$.
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