The rms speed of a gas have the right to be calculated utilizing the adhering to rule:Vrms = sqrt ( 3RT / M) where:R is the gas consistent = 8.314T is the temperature = 29 + 273 = 302 degrees kelvinM is the molar mass of the gas (oxygen) = 2*16 = 32 grams = 0.032 kgSubstitute in the equation to get Vrms as follows:Vrms = sqrt <(3*8.314*302) / (0.032)> = 485.05 meters/sec

The rms speed of an oxygen gas molecule : 485.17 m/s

Additional explanation

Kinetic Molecular Theory (KMT) claims that a gas consists of molecules that relocate at a consistent and random speed. The collisions in between molecules are perfectly elastic so that no power is wasted.

The molecules move in straight lines till they collide

Energy bereason this activity is expressed as Kinetic power (KE) which deserve to be formulated as:


The average kinetic energy value is just affected by temperature alters. The greater the temperature, the average kinetic power of the molecule increases

This molecule is extremely tiny once compared to the distance in between molecules, so the volume of gas has greatly empty space

Gas pwrite-ups move randomly (both speed and also direction , as vector)

Average velocities of gases deserve to be expressed as root-mean-square avereras. (V rms)


R = gas consistent, T = temperature, Mm = molar mass of the gas particles

From the question

R= 8.314 J/mol K

T = 29 + 273 = 302 K

Mm = molar mass O₂ = 2.16 = 32 g/mol = 32.10-3 kg/mol


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Keywords: Kinetic Molecular Theory, Collisions, The average kinetic energy, the rms rate, gas molecule