warm water at 75 °C. During mixing, heat is shed to the surroundings at the price of 30 kJ/s. What is the temperature of the warm water stream? Assume the specific heat of water is constant at 4.18 kJ/(kg·K).

You are watching: A stream of warm water is produced in a steady-flow



Explanation:

The given information is as follows.

*
= 0.8 kg/s = 800 g,
*

*
= 1 kg = 1000 g,
*
= (75 - T),

*
= T - 25

Now, according to the regulation of conservation of energy,

*

*
+ 30000

250.8 - 3.34T = 4.18T - 104.5 + 30

T =

*

=

*

Therefore, we have the right to conclude that temperature of the warmth water stream is

*
.



What is the pressure of influence of a 100 kg diver who drops into a swimming pool and also hits the surchallenge of the water and also involves a st

slrfc.org:

F = 53153.36

Explanation:

In order to fix this difficulty, we should first use the principle of conservation of power which is transdeveloped from potential energy to kinetic, in this method we can determine the velocity at which the perchild enters the water.

*

where:

m = mass = 100

g = gravity acceleration = 9.81

h = elevation = 9

v = velocity

Now replacing we have the right to determinate the velocity.

*
" alt="v^2=2*g*h\v=sqrt2*g*h\v=sqrt2*9.81*9\v = 13.28" align="absmiddle" class="latex-formula">

Then we have the right to calculate the momentum which have the right to be calculated as the product of pressure by time, this momentum is also equal to the product of mass by velocity.

See more: The Journal Entry To Record Depletion Includes, Journalizing Adjusting Entries For Depletion

*

Now replacing:

F = impact pressure

t = time = 0.025

m = 100

v = velocity = 13.28

*
" alt="F*0.025=100*13.28\F=53153.36" align="absmiddle" class="latex-formula">


8 0
7 months ago

A wind generator can have 2, 3, or 4 knives. The even more chisels, the greater the power of the turbine. Write a duty via one input
ad-work-related <718>

slrfc.org:

MATLAB Script:

cshed all

clear

clc

fprintf("Number of knives = 2: ------------------------- ")

power(2)

fprintf(" Number of blades = 3: ------------------------- ")

power(3)

fprintf(" Number of blades = 4: ------------------------- ")

power(4)

feature power(n)

switch n % n = variety of blades

situation 2

disp("Low Power")

situation 3

disp("Medium Power")

case 4

disp("High Power")

otherwise

disp("Invalid variety of blades")

end

end

Explanation:


6 0
11 months ago

An object has an acceleration of 6m/s/s. If the net pressure was tripled and also the mass was doubled, then the new acceleration would certainly
Vaselesa <24>
Acceleration = Force / mass New acceleration = 3F / 2m = 1.5 x the old acc = 9 m/s/s
5 0
5 months ago

Two similar loudspeakers 2.00 m acomponent are emitting sound waves into a room wright here the rate of sound is 340 m/s. Abby is standi
ki77a <65>

slrfc.org:

The lowest possible frequency of sound for which this is feasible is 1307.69 Hz

Explanation:

From the question, Abby is standing 5.00m in front of one of the speakers, perpendicular to the line joining the speakers.

First, we will determine his distance from the second speaker making use of the Pythagorean theorem

l₂ = √(2.00²+5.00²)

l₂ = √4+25

l₂ = √29

l₂ = 5.39 m

Hence, the path distinction is

ΔL = l₂ - l₁

ΔL = 5.39 m - 5.00 m

ΔL = 0.39 m

From the formula for terrible interference

ΔL = (n+1/2)λ

where n is any kind of integer and λ is the wavelength

n = 1 in this case, the lowest possible frequency corresponds to the largest wavelength, which coincides to the smallest worth of n.

Then,

0.39 = (1+ 1/2)λ

0.39 = (3/2)λ

0.39 = 1.5λ

∴ λ = 0.39/1.5

λ = 0.26 m

From

v = fλ

f = v/λ

f = 340 / 0.26

f = 1307.69 Hz

Hence, the lowest possible frequency of sound for which this is possible is 1307.69 Hz.


5 0
8 months ago
How does electric potential energy readjust within a spring
a_sh-v <17>
It gets more power5ful case of the coil affect
4 0
10 months ago
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